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The isstraight () function, the isFlush () function,andthe isStraightFlush() function are also tricky. Here is the i sF lus h ( ) function: int Hand: :isFlush() 1 for (int i = 1; i < size; i++) if (cards[i].suit!= cards[O].suit - > return 0; return 1;

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This compares the sui t of each of the second through fifth cards (card [ l] through card [ 41). If any of these are not thesame, then we know immediately that the hand is not a flush and can return 0. If the loop terminates naturally, then all four pairs match and 1 is returned. Here is the Deck class: #include "Rand0m.h" #include 'Hand.h" class Deck { public: Deck(); void shuffle(); void deal(Hand&, private: unsigned top; Card cards[52]; Random random; 1;

unsigned =5>;

It uses the Random class in its shu f f 1 e ( ) function. Note that the random object is declared as a private member since it is used only by another member function: void 1 Deck::deal(Hand& hand, unsigned size=5)

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Intellectual distance is a term used to describe how close two ideas are to each other in this case, how close the structure of the real-world problem is to the structure of the solution. www.omg.org, or search with the keyword UML.

for (int i = 0; i < size; i++) hand.cards[i] = cards[top++]; hand.sort();

The top member always locates the top of the deck; i.e., the next card to be dealt. So the deal ( ) function copies the top five cards off the deck into the hand's cards array. Then it sorts the hand. The Deck's constructor initializes all 52 cards in the deck, int the order two of clubs, three of clubs, four of clubs,..., ace of spades: Deck::Deck() 1 for (int i = 0; i < 52; i++) { cards[i] .rank = Rank(i%l3); cards[i].suit= Suit(i/l3); 1 top = 0;

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So if hands are dealt without shuffling first, the first hand would be the straight flush of two through six of clubs. Finally, here is the shu f f 1 e ( ) function: void Deck::shuffle() for (int i = 0; i < 52; i++) int j = random.integer(O, Card c = cards[i]; cards[i] = cards[j]; cards[j] = c; > top = 0; { 51); // do 52 random swaps

It swaps the cards in each of the 52 elements with the card in a randomly selected element of the deck s cards array The implementations of the other functions are left as exercises. (See Problem 11.18.) 11.15

relationship, the base class (the more general class) will contain all common attributes. The derived class (the more specialized class) will inherit all the common attributes from the base class. For example, if one group of entities consists of vehicles and the other group of cars, we can use inheritance. The cars can inherit from the vehicles. The cars can share many of the attributes and operations of the vehicle class. All the common attributes can be located in the base class. The derived class will automatically inherit those attributes. This sharing saves e ort.

Implement the following class hierarchy:

Here are the abstract base classes: class Shape { publx: virtual void print0 = 0; virtual float area0 = 0; 1; class TwoDimensional : public Shape { public: virtual float perimeter0 = 0; 1; class ThreeDimensional : public Shape { public: virtual float volume0 = 0;

Note that the print ( ) function and the area ( ) function prototypes are the same for all classes in this hierarchy, so their interfaces (pure virtual functions) are placed in the Shape base class, But only two-dimensional shapes have perimeters, and only three-dimensional shapes have volumes, so their interfaces are placed in the appropriate second-level ABCs.

Here is the Circle class:

Draw an object model that identifies all the commonalities between cars and vehicles. Fig. 11-1 shows that cars and vehicles both have bodies, engines, wheels (maybe not four), headlights, brand names, manufacturer, and cost. (There are probably many more.)

class Circle : public TwoDimensional { public: Circle(float r) : radius(r) { } void print0 { tout cc "Shape is a circle.\n"; float perimeter0 { return 2*pi*radius; } float area0 { return pi*radius*radius; } . private: float radius; >;

Here are two of the seven concrete derived classes:

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