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The functions in the ovals are methods of the classes in the object model. The patron object can borrow and return copies. The librarian actor is not an object on the object model. The librarian in the use case shows that some functions for instance, catalog and shelve books are not functions available to the patron.

Two of the tests depend upon whether the second from last letter is a vowel, so we define a little boolean function i svowel ( ) for testing that condition:

int isvowel(char c) 11

return (c == 'a'

strip-space element (XSL), 139 Structure(s): attribute, 36 38 document, 38 39 element, 34 36 logical, 6 7 physical, 7, 8 schema, 44 schema for, 48 57 tree, 185 Structured Query Language (SQL), 185 Style: border, 70 72 font, 69 Style rules, 185 Style sheets, 65 de nition of, 185 XSL, 128 130 sub-resource (XPointer), 147 substring-after()function (XPath), 109 substring-before()function (XPath), 109 substring()function (XPath), 109 sum()function (XPath), 111 Sun, 13 SVG (Scalable Vector Graphics), 20 Sybase, 13, 14 Symmetric key encryption, 174 Synchronized Multimedia Integration Language (SMIL), 3, 20 SYNTAX_ERR, 91 Tabs, 19 </tag>, 7 <tag>, 7 Tags: de nition of, 4 DTDs, 23 structure of, 7 Tail accessors (XPath), 114 Target namespaces, 46, 49 targetNamespace, 51 Tdtd, 20 Templates: de nition of, 185 XSLT, 136 139 Text, 26 CDATA for, 18 standards for, 187 188 Text, 81, 83 Text-align property, 70 Text-decoration, 69 Text editors, 19 "TEXT" le type code, 191, 192 text/plain, 189

Draw a directed graph showing the dependencies between the variables in the code in Example 9.7. Use solid lines for data dependencies and dashed lines for control dependencies. From the graph in Fig. 9-6, we can see that the output slice will start from the only output, z. The tokens z, z, y , z, and 0 from the statements z=z+y and z=0 are added to the slice. Next, the tokens x and 0 are added from the statement while x> 0. Next, the tokens, x , x , and 1 from the statement x=x+1 are added. This exhausts the statements, so everything in this program is in the output slice for the variable z.

u );

The test driver repeatedly reads a word, prints it, pluralizes it, and prints it again. The loop terminates when the user enters a single blank for a word: #include #include <iostream.h> <string.h>

void pluralize(char*); main0 1 char word[80]; for (;;) 1 cin.getline(word, 80); if (*word == ' ') break; tout << '\tThe singular is [" << word << "].\n"; pluralize(word); tout << "\t The plural is [" << word << "].\n"; ,

We assume that names have no more than 25 characters and that there will be no more than 25 names. We ll read all the input in at once and store it all in a single buffer. Since each name will be terminated with a NUL character, the buffer needs to be large enough to hold 25*(20 + 1) + 1 characters (25 21-character strings plus one last NUL character). The program is modularized into five function calls. The call input ( bu f f er ) reads everything intothe buffer.Thecall tokenize(name, numNames, buffer) tokenizes the buffer, storing pointers to its names in the name array and returning the number of names in nurnNames. The call print(name, numNames ) prints all the names that are stored in buf f er. The call sort(name, numNames ) does an indirect sort on the names stored in buf f er by rearranging the pointers stored in the name array. #include #include const const const void void void void main0 char* name[maxNumNames]; char buffer[bufferLength+l]; int nurnNames; input(buffer); tokenize(name, num.Names, buffer); print(name, numNames); sort(name, numNames); print(name, num.Names); ciostream.h> cstring.h>